{
"query": {
"display": "$$3x^{2}+30x+y+79=0$$",
"symbolab_question": "CONIC#3x^{2}+30x+y+79=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(-5,-4),p=-\\frac{1}{12}"
},
"steps": {
"type": "interim",
"title": "$$3x^{2}+30x+y+79=0:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(-5,\\:-4\\right),\\:$$and focal length $$|p|=\\frac{1}{12}$$",
"input": "3x^{2}+30x+y+79=0",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$3x^{2}+30x+y+79=0\\:$$in the standard form",
"input": "3x^{2}+30x+y+79=0",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "y=-3x^{2}-30x-79"
},
{
"type": "interim",
"title": "Complete the square $$-3x^{2}-30x-79:{\\quad}-3\\left(x+5\\right)^{2}-4$$",
"input": "-3x^{2}-30x-79",
"steps": [
{
"type": "step",
"primary": "Write $$-3x^{2}-30x-79\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-3$$"
],
"result": "-3\\left(x^{2}+10x+\\frac{79}{3}\\right)"
},
{
"type": "interim",
"title": "$$2a=10{\\quad:\\quad}a=5$$",
"input": "2a=10",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=10",
"result": "a=5",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{10}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=5"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$5^{2}\\:$$",
"result": "-3\\left(x^{2}+10x+\\frac{79}{3}+5^{2}-5^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}+10x+5^{2}=\\left(x+5\\right)^{2}$$",
"Complete the square"
],
"result": "-3\\left(\\left(x+5\\right)^{2}+\\frac{79}{3}-5^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-3\\left(x+5\\right)^{2}-4"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y=-3\\left(x+5\\right)^{2}-4"
},
{
"type": "step",
"primary": "Add $$4$$ to both sides",
"result": "y+4=-3\\left(x+5\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-3$$",
"result": "-\\frac{1}{3}\\left(y+4\\right)=\\left(x+5\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-\\frac{1}{12}\\right)\\left(y-\\left(-4\\right)\\right)=\\left(x-\\left(-5\\right)\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-\\frac{1}{12}\\right)\\left(y-\\left(-4\\right)\\right)=\\left(x-\\left(-5\\right)\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(-5,\\:-4\\right),\\:p=-\\frac{1}{12}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-(-5))^{2}}{4(-\\frac{1}{12})}-4",
"displayFormula": "4(-\\frac{1}{12})(y-(-4))=(x-(-5))^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\frac{47}{12}",
"displayFormula": "y=-\\frac{47}{12}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-5,-4)",
"(-5,-\\frac{49}{12})"
],
"pointsDecimal": [
{
"fst": -5,
"snd": -4
},
{
"fst": -5,
"snd": -4.083333333333333
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{1}{12})(y-(-4))=(x-(-5))^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -6.095238095238095,
"xMax": 1.5238095238095237,
"yMin": -5.666666666666666,
"yMax": 1.9523809523809526
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is 3x^2+30x+y+79=0 ?
The solution to 3x^2+30x+y+79=0 is Parabola with (h,k)=(-5,-4),p=-1/12