{
"query": {
"display": "$$-x^{2}+12x-12y-96=0$$",
"symbolab_question": "CONIC#-x^{2}+12x-12y-96=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(6,-5),p=-3"
},
"steps": {
"type": "interim",
"title": "$$-x^{2}+12x-12y-96=0:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(6,\\:-5\\right),\\:$$and focal length $$|p|=3$$",
"input": "-x^{2}+12x-12y-96=0",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$-x^{2}+12x-12y-96=0\\:$$in the standard form",
"input": "-x^{2}+12x-12y-96=0",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "12y=-x^{2}+12x-96"
},
{
"type": "step",
"primary": "Divide by $$12$$",
"result": "y=-\\frac{x^{2}}{12}+x-8"
},
{
"type": "interim",
"title": "Complete the square $$-\\frac{x^{2}}{12}+x-8:{\\quad}-\\frac{1}{12}\\left(x-6\\right)^{2}-5$$",
"input": "-\\frac{x^{2}}{12}+x-8",
"steps": [
{
"type": "step",
"primary": "Write $$-\\frac{x^{2}}{12}+x-8\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-\\frac{1}{12}$$"
],
"result": "-\\frac{1}{12}\\left(x^{2}-12x+96\\right)"
},
{
"type": "interim",
"title": "$$2a=-12{\\quad:\\quad}a=-6$$",
"input": "2a=-12",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=-12",
"result": "a=-6",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{-12}{2}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2a}{2}=\\frac{-12}{2}",
"result": "a=-6",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2a}{2}:{\\quad}a$$",
"input": "\\frac{2a}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=a"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7n/9TIosDfOyZXH4usT9jsy061ljBSPJeENOw2efoSWuFFDuzzgIzA1F36c+SAFGgRSpN33oxZMojoqvYhvSJACLkpiVA7S8UT8ieezZKu6pQyGeXuoJHAaVrX92ZjOTT"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{-12}{2}:{\\quad}-6$$",
"input": "\\frac{-12}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{12}{2}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{12}{2}=6$$",
"result": "=-6"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7GKWtQW4fbFStcswMIqzf9QCWKUbvV6WK3fDUgFtg3Q8IVlRpyxl4O+CcU61LkQcQZEt3ZXAiqUE0HIXrrrezJHZKl2mV4AlztiApTAFigz0s7e1hziQhbs6o+Enn0k2JsIjaxJ4DvjTb2fbKjbvtlQ=="
}
},
{
"type": "step",
"result": "a=-6"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7h0qN/2Oj/0NKityiSZQNPhyOUtErWNRXbTqqjj69E3uDOgvFz5BQb7ambH6EyJiMsvosUnsUtTWgbhUA2bNJ7TAXz9SyasZsQdp2/zXYohmJLbrsy9PUkt1PkbIMRxhVzPywKoVbgpEyLnOm1p35SKygCIJkvFvbYplW0YhTWI3nV0tYK1uGM6+4ZymjYHSGC4rp4BFqIrALjtPWFCnyz+KLha0Euv8ogMrAdOPBeaBOC1XxR5OU6NuvCKo2efCi0mGkD3+4P3JH8+HqppYV9TkrIeytDe07pErV7r9V36yVrUYSIPtChMsh4ws3iNwf0GoqR269Z5nVqV2M25/NwcrOCQn16lcBUSDyTTKFAYd62GGnKtBN1rhK9Rxmb8qwkRCWtDruq67zpEO6MUu1LoCKEjxik5rtiNxmiu8QLCw23KRiFexCf0tZxyHbMvr9"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(-6\\right)^{2}\\:$$",
"result": "-\\frac{1}{12}\\left(x^{2}-12x+96+\\left(-6\\right)^{2}-\\left(-6\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}-12x+\\left(-6\\right)^{2}=\\left(x-6\\right)^{2}$$",
"Complete the square"
],
"result": "-\\frac{1}{12}\\left(\\left(x-6\\right)^{2}+96-\\left(-6\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-\\frac{1}{12}\\left(x-6\\right)^{2}-5"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y=-\\frac{1}{12}\\left(x-6\\right)^{2}-5"
},
{
"type": "step",
"primary": "Add $$5$$ to both sides",
"result": "y+5=-\\frac{1}{12}\\left(x-6\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-\\frac{1}{12}$$",
"result": "-12\\left(y+5\\right)=\\left(x-6\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-3\\right)\\left(y-\\left(-5\\right)\\right)=\\left(x-6\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-3\\right)\\left(y-\\left(-5\\right)\\right)=\\left(x-6\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(6,\\:-5\\right),\\:p=-3"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-6)^{2}}{4(-3)}-5",
"displayFormula": "4(-3)(y-(-5))=(x-6)^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-2",
"displayFormula": "y=-2",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(6,-5)",
"(6,-8)"
],
"pointsDecimal": [
{
"fst": 6,
"snd": -5
},
{
"fst": 6,
"snd": -8
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-3)(y-(-5))=(x-6)^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -27.75,
"xMax": 39.75,
"yMin": -38.75,
"yMax": 28.75
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is -x^2+12x-12y-96=0 ?
The solution to -x^2+12x-12y-96=0 is Parabola with (h,k)=(6,-5),p=-3