{
"query": {
"display": "$$12y+x^{2}=0$$",
"symbolab_question": "CONIC#12y+x^{2}=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(0,0),p=-3"
},
"steps": {
"type": "interim",
"title": "$$12y+x^{2}=0:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:$$and focal length $$|p|=3$$",
"input": "12y+x^{2}=0",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$12y+x^{2}=0\\:$$in the standard form:$${\\quad}4\\left(-3\\right)\\left(y-0\\right)=\\left(x-0\\right)^{2}$$",
"input": "12y+x^{2}=0",
"steps": [
{
"type": "step",
"primary": "Subtract $$x^{2}$$ from both sides",
"result": "12y+x^{2}-x^{2}=0-x^{2}"
},
{
"type": "step",
"primary": "Refine",
"result": "12y=-x^{2}"
},
{
"type": "step",
"primary": "Divide both sides by $$-1$$",
"result": "\\frac{12y}{-1}=\\frac{-x^{2}}{-1}"
},
{
"type": "step",
"primary": "Simplify",
"result": "-12y=x^{2}"
},
{
"type": "step",
"primary": "Factor $$4$$",
"result": "4\\cdot\\:\\frac{-12}{4}y=x^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "4\\left(-3\\right)y=x^{2}"
},
{
"type": "step",
"primary": "Rewrite as",
"result": "4\\left(-3\\right)\\left(y-0\\right)=\\left(x-0\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7L1hU6UYRNlySJ7LfHaV09Rnz2PGleSdJAw6jQ13MnVgjGsBIMn028UBVvff51AwIUo+0skB3JhOoVsRyoC4GXjh2no6HYikYL/uXZaE/9Y/apXczCuSTG7CwPMGE80Aa0R2ezmQjS5W1eo+O0ihzAHql8XXPq6bNQlMm+36iNhnKjiytAWaK9jbpnb3r31dEBBvyJMgy3QgMp5ubn9U5SYHrgyXxvQqLRZoailGYyyYfT9nLmYg2mxBVBWxtPcsS"
}
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:p=-3"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{x^{2}}{4(-3)}+0",
"displayFormula": "4(-3)y=x^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=3",
"displayFormula": "y=3",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)",
"(0,-3)"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
},
{
"fst": 0,
"snd": -3
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-3)(y)=x^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -33.75,
"xMax": 33.75,
"yMin": -33.75,
"yMax": 33.75
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is 12y+x^2=0 ?
The solution to 12y+x^2=0 is Parabola with (h,k)=(0,0),p=-3