What is the radius x^2+y^2-32x-60y+1122=0 ?

The radius x^2+y^2-32x-60y+1122=0 is r=sqrt(34)

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radius x^2+y^2-32x-60y+1122=0

radius

r = 34

Solution steps

x^{2} + y^{2} - 32 x - 60 y + 1122 = 0

Rewrite

x^{2} + y^{2} - 32 x - 60 y + 1122 = 0

in the form of the standard circle equation

(x - 16)^{2} + (y - 30)^{2} = (34)^{2}

Therefore the circle properties are:

(a, b) = (16, 30), r = 34

And the radius is:

r = 34

What is the radius x^2+y^2-32x-60y+1122=0 ?
The radius x^2+y^2-32x-60y+1122=0 is r=sqrt(34)