What is the radius 36x^2+36y^2-24x+36y-245=0 ?

The radius 36x^2+36y^2-24x+36y-245=0 is r=sqrt(43/6)

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radius 36x^2+36y^2-24x+36y-245=0

radius

r = \frac{43}{6}

Solution steps

36 x^{2} + 36 y^{2} - 24 x + 36 y - 245 = 0

Rewrite

36 x^{2} + 36 y^{2} - 24 x + 36 y - 245 = 0

in the form of the standard circle equation

(x - \frac{1}{3})^{2} + (y - (- \frac{1}{2}))^{2} = (\frac{43}{6})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{3}, - \frac{1}{2}), r = \frac{43}{6}

And the radius is:

r = \frac{43}{6}

What is the radius 36x^2+36y^2-24x+36y-245=0 ?
The radius 36x^2+36y^2-24x+36y-245=0 is r=sqrt(43/6)