What is the radius 5x^2+5y^2+10x-20y=55 ?

The radius 5x^2+5y^2+10x-20y=55 is r=4

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radius 5x^2+5y^2+10x-20y=55

radius

r = 4

Solution steps

5 x^{2} + 5 y^{2} + 10 x - 20 y = 55

Rewrite

5 x^{2} + 5 y^{2} + 10 x - 20 y = 55

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 4

And the radius is:

r = 4

What is the radius 5x^2+5y^2+10x-20y=55 ?
The radius 5x^2+5y^2+10x-20y=55 is r=4