What is the radius x^2+y^2+14x-2y+25=0 ?

The radius x^2+y^2+14x-2y+25=0 is r=5

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radius x^2+y^2+14x-2y+25=0

radius

r = 5

Solution steps

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

Rewrite

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 7, 1), r = 5

And the radius is:

r = 5