de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

center 4x^2+4y^2+40y+75=0

Lösung

center

4 x^{2} + 4 y^{2} + 40 y + 75 = 0

Lösung

(0, - 5)

Schritte zur Lösung

4 x^{2} + 4 y^{2} + 40 y + 75 = 0

Rewrite

4 x^{2} + 4 y^{2} + 40 y + 75 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 5))^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, - 5), r = \frac{5}{2}

And the center is:

(0, - 5)

Graph

Beliebte Beispiele

center (x+8/3)^2+y^2=1

ce n t er (x + \frac{8}{3})^{2} + y^{2} = 1

center (x-3)^2+(y+4)^2= 16/9

ce n t er (x - 3)^{2} + (y + 4)^{2} = \frac{16}{9}

center x^2-2x+y^2-4y=0

ce n t er x^{2} - 2 x + y^{2} - 4 y = 0

center x^2+y^2+6x-8y+16=0

ce n t er x^{2} + y^{2} + 6 x - 8 y + 16 = 0

center 9x^2+9y^2=729

ce n t er 9 x^{2} + 9 y^{2} = 729