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Beliebt Geometry >

center (x-3)^2+(y+4)^2= 16/9

Lösung

center

(x - 3)^{2} + (y + 4)^{2} = \frac{16}{9}

Lösung

(3, - 4)

Schritte zur Lösung

(x - 3)^{2} + (y + 4)^{2} = \frac{16}{9}

Rewrite

(x - 3)^{2} + (y + 4)^{2} = \frac{16}{9}

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 4))^{2} = (\frac{4}{3})^{2}

Therefore the circle properties are:

(a, b) = (3, - 4), r = \frac{4}{3}

And the center is:

(3, - 4)

Graph

Beliebte Beispiele

center x^2-2x+y^2-4y=0

ce n t er x^{2} - 2 x + y^{2} - 4 y = 0

center x^2+y^2+6x-8y+16=0

ce n t er x^{2} + y^{2} + 6 x - 8 y + 16 = 0

center 9x^2+9y^2=729

ce n t er 9 x^{2} + 9 y^{2} = 729

center x^2+y^2+3x+4y+4=0

ce n t er x^{2} + y^{2} + 3 x + 4 y + 4 = 0

center (x-9)^2+(y+4)^2=25

ce n t er (x - 9)^{2} + (y + 4)^{2} = 25