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Beliebt Geometry >

center x^2+y^2+8y=2x+20

Lösung

center

x^{2} + y^{2} + 8 y = 2 x + 20

Lösung

(1, - 4)

Schritte zur Lösung

x^{2} + y^{2} + 8 y = 2 x + 20

Rewrite

x^{2} + y^{2} + 8 y = 2 x + 20

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 37

And the center is:

(1, - 4)

Graph

Beliebte Beispiele

center sqrt(13)^2=(x-(-4))^2+(y-(-3))^2

ce n t er 13^{2} = (x - (- 4))^{2} + (y - (- 3))^{2}

center 13.8+x^2+y^2=17

ce n t er 13.8 + x^{2} + y^{2} = 17

center 3x^2+3y^2-18x-18y+42=0

ce n t er 3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

center (x-5)^2+(y-1)^2=49

ce n t er (x - 5)^{2} + (y - 1)^{2} = 49

center x^2+(y-1)^2=36

ce n t er x^{2} + (y - 1)^{2} = 36