What is the center 3x^2+3y^2-18x-18y+42=0 ?

The center 3x^2+3y^2-18x-18y+42=0 is (3,3)

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center 3x^2+3y^2-18x-18y+42=0

center

(3, 3)

Solution steps

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

Rewrite

3 x^{2} + 3 y^{2} - 18 x - 18 y + 42 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 3), r = 2

And the center is:

(3, 3)

What is the center 3x^2+3y^2-18x-18y+42=0 ?
The center 3x^2+3y^2-18x-18y+42=0 is (3,3)