What is the center (x+4)^2+(y-10)^2=274 ?

The center (x+4)^2+(y-10)^2=274 is (-4,10)

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center (x+4)^2+(y-10)^2=274

center

(x + 4)^{2} + (y - 10)^{2} = 274

(- 4, 10)

Solution steps

(x + 4)^{2} + (y - 10)^{2} = 274

Rewrite

(x + 4)^{2} + (y - 10)^{2} = 274

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 10)^{2} = (274)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 10), r = 274

And the center is:

(- 4, 10)

x^{2} + y^{2} - 10 x + 12 y + 25 = 0

y^{2} + x^{2} - 12 x + 18 y + 116 = 0

16 x^{2} + 16 y^{2} + 8 x - 3 y = - 1

x^{2} + y^{2} - 4 x + 2 = 0

(x + 2)^{2} + (y - 1)^{2} = 9

What is the center (x+4)^2+(y-10)^2=274 ?
The center (x+4)^2+(y-10)^2=274 is (-4,10)