What is the center (X+1)^2+(Y+6)^2=19 ?

The center (X+1)^2+(Y+6)^2=19 is (-1,-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

center (X+1)^2+(Y+6)^2=19

center

(- 1, - 6)

Solution steps

(X + 1)^{2} + (Y + 6)^{2} = 19

Rewrite

(X + 1)^{2} + (Y + 6)^{2} = 19

in the form of the standard circle equation

(X - (- 1))^{2} + (Y - (- 6))^{2} = (19)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 6), r = 19

And the center is:

(- 1, - 6)

What is the center (X+1)^2+(Y+6)^2=19 ?
The center (X+1)^2+(Y+6)^2=19 is (-1,-6)