What is the center (X+1)^2+(Y+6)^2=19 ?

The center (X+1)^2+(Y+6)^2=19 is (-1,-6)

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center (X+1)^2+(Y+6)^2=19

center

(X + 1)^{2} + (Y + 6)^{2} = 19

(- 1, - 6)

Solution steps

(X + 1)^{2} + (Y + 6)^{2} = 19

Rewrite

(X + 1)^{2} + (Y + 6)^{2} = 19

in the form of the standard circle equation

(X - (- 1))^{2} + (Y - (- 6))^{2} = (19)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 6), r = 19

And the center is:

(- 1, - 6)

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

x^{2} + y^{2} - 4 x - 5 = 0

(x - 3)^{2} + (y + 5)^{2} = 49

10 x^{2} + 10 y^{2} - 10 x - y - 137 = 0

x^{2} + y^{2} - 10 x + 4 y + 20 = 0

What is the center (X+1)^2+(Y+6)^2=19 ?
The center (X+1)^2+(Y+6)^2=19 is (-1,-6)