What is the center x^2+y^2-20x+36y+353=0 ?

The center x^2+y^2-20x+36y+353=0 is (10,-18)

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center x^2+y^2-20x+36y+353=0

center

x^{2} + y^{2} - 20 x + 36 y + 353 = 0

(10, - 18)

Solution steps

x^{2} + y^{2} - 20 x + 36 y + 353 = 0

Rewrite

x^{2} + y^{2} - 20 x + 36 y + 353 = 0

in the form of the standard circle equation

(x - 10)^{2} + (y - (- 18))^{2} = (71)^{2}

Therefore the circle properties are:

(a, b) = (10, - 18), r = 71

And the center is:

(10, - 18)

(x + 1)^{2} + (y - 5)^{2} = 4

(x + 1)^{2} + (y + 3)^{2} = 9

(x - 5)^{2} + (y + 1)^{2} = 16

(x - 5)^{2} + (y + 1)^{2} = 12

x^{2} + y^{2} + 6 x - 16 y + 48 = 0

What is the center x^2+y^2-20x+36y+353=0 ?
The center x^2+y^2-20x+36y+353=0 is (10,-18)