What is the center (x-17)^2+(y+5)^2=144 ?

The center (x-17)^2+(y+5)^2=144 is (17,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

center (x-17)^2+(y+5)^2=144

center

(17, - 5)

Solution steps

(x - 17)^{2} + (y + 5)^{2} = 144

Rewrite

(x - 17)^{2} + (y + 5)^{2} = 144

in the form of the standard circle equation

(x - 17)^{2} + (y - (- 5))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (17, - 5), r = 12

And the center is:

(17, - 5)

What is the center (x-17)^2+(y+5)^2=144 ?
The center (x-17)^2+(y+5)^2=144 is (17,-5)