What is the center x^2+y^2+2x-6y+6=0 ?

The center x^2+y^2+2x-6y+6=0 is (-1,3)

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center x^2+y^2+2x-6y+6=0

center

x^{2} + y^{2} + 2 x - 6 y + 6 = 0

(- 1, 3)

Solution steps

x^{2} + y^{2} + 2 x - 6 y + 6 = 0

Rewrite

x^{2} + y^{2} + 2 x - 6 y + 6 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 2

And the center is:

(- 1, 3)

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

x^{2} + 6 x + y^{2} = 7

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

x^{2} + 6 x + y^{2} - 2 y - 26 = 0

(x - 1)^{2} + (y + 5)^{2} = 36