What is the center (x-6)^2+(y+5)^2=16 ?

The center (x-6)^2+(y+5)^2=16 is (6,-5)

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center (x-6)^2+(y+5)^2=16

center

(x - 6)^{2} + (y + 5)^{2} = 16

(6, - 5)

Solution steps

(x - 6)^{2} + (y + 5)^{2} = 16

Rewrite

(x - 6)^{2} + (y + 5)^{2} = 16

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (6, - 5), r = 4

And the center is:

(6, - 5)

x^{2} + y^{2} + 20 x - 18 y + 145 = 0

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x^{2} + y^{2} - 3 x - 4 y + 4 = 0

2 x^{2} + 2 y^{2} + 4 x - 8 y - 22 = 0

x^{2} + y^{2} - 4 x + 2 y - 15 = 0