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Beliebt Geometry >

center 2x^2+2y^2+4x-8y-22=0

Lösung

center

2 x^{2} + 2 y^{2} + 4 x - 8 y - 22 = 0

Lösung

(- 1, 2)

Schritte zur Lösung

2 x^{2} + 2 y^{2} + 4 x - 8 y - 22 = 0

Rewrite

2 x^{2} + 2 y^{2} + 4 x - 8 y - 22 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 4

And the center is:

(- 1, 2)

Graph

Beliebte Beispiele

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ce n t er x^{2} + y^{2} - 4 x + 2 y - 15 = 0

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