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Beliebt Geometry >

center x^2-7x+y^2+8y-14=0

Lösung

center

x^{2} - 7 x + y^{2} + 8 y - 14 = 0

Lösung

(\frac{7}{2}, - 4)

Schritte zur Lösung

x^{2} - 7 x + y^{2} + 8 y - 14 = 0

Rewrite

x^{2} - 7 x + y^{2} + 8 y - 14 = 0

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- 4))^{2} = (\frac{13}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - 4), r = \frac{13}{2}

And the center is:

(\frac{7}{2}, - 4)

Graph

Beliebte Beispiele

center 3(x-5)^2+3(y+9)^2=48

ce n t er 3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

center x^2+y^2+10x-6y+15=0

ce n t er x^{2} + y^{2} + 10 x - 6 y + 15 = 0

center a^2+b^2=36

ce n t er a^{2} + b^{2} = 36

center 9x^2+9y^2+42x-54y+49=0

ce n t er 9 x^{2} + 9 y^{2} + 42 x - 54 y + 49 = 0

center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2

ce n t er (x - (- 5))^{2} + (y - (7))^{2} = (11)^{2}