What is the center 3(x-5)^2+3(y+9)^2=48 ?

The center 3(x-5)^2+3(y+9)^2=48 is (5,-9)

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center 3(x-5)^2+3(y+9)^2=48

center

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

(5, - 9)

Solution steps

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

Rewrite

3 (x - 5)^{2} + 3 (y + 9)^{2} = 48

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 9))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, - 9), r = 4

And the center is:

(5, - 9)

x^{2} + y^{2} + 8 y = 32

x^{2} + y^{2} - 6 x + 8 y - 11 = 0

x^{2} + y^{2} + 8 x - 2 y + 15 = 0

x^{2} + y^{2} - 12 x + 4 y = - 2

x^{2} + y^{2} + 10 x - 6 y + 15 = 0

What is the center 3(x-5)^2+3(y+9)^2=48 ?
The center 3(x-5)^2+3(y+9)^2=48 is (5,-9)