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Beliebt Geometry >

center x^2+(y+2)^2=4

Lösung

center

x^{2} + (y + 2)^{2} = 4

Lösung

(0, - 2)

Schritte zur Lösung

x^{2} + (y + 2)^{2} = 4

Rewrite

x^{2} + (y + 2)^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, - 2), r = 2

And the center is:

(0, - 2)

Graph

Beliebte Beispiele

center (x-5)^2+(y+2)^2=16

ce n t er (x - 5)^{2} + (y + 2)^{2} = 16

center 2x^2+2y^2+16x+20y+18=0

ce n t er 2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

center 2x^2+2y^2-12x+4y-12=0

ce n t er 2 x^{2} + 2 y^{2} - 12 x + 4 y - 12 = 0

center 4(x-3)^2+4y^2=4

ce n t er 4 (x - 3)^{2} + 4 y^{2} = 4

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ce n t er x^{2} + y^{2} + 2 x - 8 y - 19 = 0