What is the center 2x^2+2y^2+16x+20y+18=0 ?

The center 2x^2+2y^2+16x+20y+18=0 is (-4,-5)

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center 2x^2+2y^2+16x+20y+18=0

center

2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

(- 4, - 5)

Solution steps

2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

Rewrite

2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 5))^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 5), r = 42

And the center is:

(- 4, - 5)

What is the center 2x^2+2y^2+16x+20y+18=0 ?
The center 2x^2+2y^2+16x+20y+18=0 is (-4,-5)