What is the center x^2+y^2+2x+2y-2=0 ?

The center x^2+y^2+2x+2y-2=0 is (-1,-1)

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center x^2+y^2+2x+2y-2=0

center

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

(- 1, - 1)

Solution steps

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

Rewrite

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 2

And the center is:

(- 1, - 1)

(x - 5)^{2} + (y - 2)^{2} = 25

9 x^{2} + 9 y^{2} - 6 x + 24 y = 19

(x - 1)^{2} + (y - 2)^{2} = 36

2 x^{2} + 2 y^{2} - 4 x - 8 y = 10

(x - 3)^{2} + (y - 2)^{2} = 1