What is the center (x-5)^2+(y-2)^2=25 ?

The center (x-5)^2+(y-2)^2=25 is (5,2)

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center (x-5)^2+(y-2)^2=25

center

(5, 2)

Solution steps

(x - 5)^{2} + (y - 2)^{2} = 25

Rewrite

(x - 5)^{2} + (y - 2)^{2} = 25

in the form of the standard circle equation

(x - 5)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 2), r = 5

And the center is:

(5, 2)