What is the center (x-1/2)^2+(y-1/2)^2= 9/4 ?

The center (x-1/2)^2+(y-1/2)^2= 9/4 is (1/2 , 1/2)

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center (x-1/2)^2+(y-1/2)^2= 9/4

center

(\frac{1}{2}, \frac{1}{2})

Solution steps

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

Rewrite

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

And the center is:

(\frac{1}{2}, \frac{1}{2})

What is the center (x-1/2)^2+(y-1/2)^2= 9/4 ?
The center (x-1/2)^2+(y-1/2)^2= 9/4 is (1/2 , 1/2)