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Beliebt Geometry >

center 2x^2+2y^2-8=0

Lösung

center

2 x^{2} + 2 y^{2} - 8 = 0

Lösung

(0, 0)

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 8 = 0

Rewrite

2 x^{2} + 2 y^{2} - 8 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

And the center is:

(0, 0)

Graph

Beliebte Beispiele

center x^2+y^2+14x-12y+4=0

ce n t er x^{2} + y^{2} + 14 x - 12 y + 4 = 0

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ce n t er x^{2} + y^{2} + 4 x + 4 y + 7 = 0

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