What is x^2+(y^2)/(16)=1 ?

The solution to x^2+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=1,b=4

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x^2+(y^2)/(16)=1

x^{2} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 1, b = 4

Solution steps

x^{2} + \frac{y ^{2}}{16} = 1

Rewrite

x^{2} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 1

(x + 1)^{2} + (y - 2)^{2} = 9

\frac{( y + 1 ) ^{2}}{4} - (x - 5)^{2} = 4

25 x^{2} - 9 y^{2} = 225

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

f (x) = x^{2} + 4 x + 4

What is x^2+(y^2)/(16)=1 ?
The solution to x^2+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=1,b=4