What is x^2+4x+y^2-2y=-1 ?

The solution to x^2+4x+y^2-2y=-1 is Circle with (a,b)=(-2,1),r=2

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x^2+4x+y^2-2y=-1

x^{2} + 4 x + y^{2} - 2 y = - 1

(a, b) = (- 2, 1), r = 2

Solution steps

x^{2} + 4 x + y^{2} - 2 y = - 1

Rewrite

x^{2} + 4 x + y^{2} - 2 y = - 1

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 2

x^{2} + y^{2} + 4 x - 18 y + 76 = 0

x^{2} + z^{2} + 4 x - 6 z + 9 = 0

(x - 6)^{2} + y^{2} = 1

(x - 7)^{2} + (y + 3)^{2} = 9

(x + 0.738)^{2} + (y + 1.119)^{2} = 6.99 6^{2}

What is x^2+4x+y^2-2y=-1 ?
The solution to x^2+4x+y^2-2y=-1 is Circle with (a,b)=(-2,1),r=2