What is (x-7)^2+(y+3)^2=9 ?

The solution to (x-7)^2+(y+3)^2=9 is Circle with (a,b)=(7,-3),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(x-7)^2+(y+3)^2=9

(x - 7)^{2} + (y + 3)^{2} = 9

(a, b) = (7, - 3), r = 3

Solution steps

(x - 7)^{2} + (y + 3)^{2} = 9

Rewrite

(x - 7)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (7, - 3), r = 3

What is (x-7)^2+(y+3)^2=9 ?
The solution to (x-7)^2+(y+3)^2=9 is Circle with (a,b)=(7,-3),r=3