What is (x-13)^2+(y+7)^2=144 ?

The solution to (x-13)^2+(y+7)^2=144 is Circle with (a,b)=(13,-7),r=12

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(x-13)^2+(y+7)^2=144

(x - 13)^{2} + (y + 7)^{2} = 144

(a, b) = (13, - 7), r = 12

Solution steps

(x - 13)^{2} + (y + 7)^{2} = 144

Rewrite

(x - 13)^{2} + (y + 7)^{2} = 144

in the form of the standard circle equation

(x - 13)^{2} + (y - (- 7))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (13, - 7), r = 12

x^{2} + (y - \frac{1}{4})^{2} = \frac{16}{9}

3 x^{2} + 3 y^{2} - 30 x + 36 y - 9 = 0

x^{2} + y^{2} + 2 x + 16 y + 61 = 0

x^{2} + y^{2} + 8 x + 18 y + 72 = 0

x^{2} + y^{2} - x - y = 8

What is (x-13)^2+(y+7)^2=144 ?
The solution to (x-13)^2+(y+7)^2=144 is Circle with (a,b)=(13,-7),r=12