What is x^2+14x+y^2-2y-50=0 ?

The solution to x^2+14x+y^2-2y-50=0 is Circle with (a,b)=(-7,1),r=10

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x^2+14x+y^2-2y-50=0

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

(a, b) = (- 7, 1), r = 10

Solution steps

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

Rewrite

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 1)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 7, 1), r = 10

(x - 2)^{2} + (y - 1.5)^{2} = 9

x^{2} + y^{2} + 2 x + 4 y - 31 = 0

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

(x - 6)^{2} + (y - 3)^{2} = 20^{2}

(x - 13)^{2} + (y + 7)^{2} = 144

What is x^2+14x+y^2-2y-50=0 ?
The solution to x^2+14x+y^2-2y-50=0 is Circle with (a,b)=(-7,1),r=10