What is 3x^2-12x+3y^2=2 ?

The solution to 3x^2-12x+3y^2=2 is Circle with (a,b)=(2,0),r=sqrt(14/3)

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3x^2-12x+3y^2=2

3 x^{2} - 12 x + 3 y^{2} = 2

(a, b) = (2, 0), r = \frac{14}{3}

Solution steps

3 x^{2} - 12 x + 3 y^{2} = 2

Rewrite

3 x^{2} - 12 x + 3 y^{2} = 2

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = (\frac{14}{3})^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = \frac{14}{3}

3 x^{2} + 3 y^{2} - 15 x - 21 y = 110

(x - 1)^{(2)} + (y + 1)^{(2)} = 4

x^{2} - 4 x + y^{2} + 6 y - 3 = 0

(x - 4)^{2} + (y + 12)^{2} + (0 - 8) = 100

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

What is 3x^2-12x+3y^2=2 ?
The solution to 3x^2-12x+3y^2=2 is Circle with (a,b)=(2,0),r=sqrt(14/3)