What is x^2-2x+1+y^2+y+2= 11/4 ?

The solution to x^2-2x+1+y^2+y+2= 11/4 is Circle with (a,b)=(1,-1/2),r=1

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x^2-2x+1+y^2+y+2= 11/4

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

(a, b) = (1, - \frac{1}{2}), r = 1

Solution steps

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

Rewrite

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{1}{2}), r = 1

(x - 6)^{2} + (y + 1)^{2} = 4

(x - 7)^{2} + (y + 5)^{2} = 4

x^{2} + y^{2} + 2 x - 10 y + 4 = 0

8 x^{2} + 8 y^{2} = 32

(2 x^{2} + 7 x) + (2 y^{2} + 4 y) = 6

What is x^2-2x+1+y^2+y+2= 11/4 ?
The solution to x^2-2x+1+y^2+y+2= 11/4 is Circle with (a,b)=(1,-1/2),r=1