What is 3x^2+3y^2-15x-21y=110 ?

The solution to 3x^2+3y^2-15x-21y=110 is Circle with (a,b)=(5/2 , 7/2),r=sqrt(331/6)

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3x^2+3y^2-15x-21y=110

3 x^{2} + 3 y^{2} - 15 x - 21 y = 110

(a, b) = (\frac{5}{2}, \frac{7}{2}), r = \frac{331}{6}

Solution steps

3 x^{2} + 3 y^{2} - 15 x - 21 y = 110

Rewrite

3 x^{2} + 3 y^{2} - 15 x - 21 y = 110

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - \frac{7}{2})^{2} = (\frac{331}{6})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, \frac{7}{2}), r = \frac{331}{6}

(x - 1)^{(2)} + (y + 1)^{(2)} = 4

x^{2} - 4 x + y^{2} + 6 y - 3 = 0

(x - 4)^{2} + (y + 12)^{2} + (0 - 8) = 100

x^{2} - 2 x + 1 + y^{2} + y + 2 = \frac{11}{4}

(x - 6)^{2} + (y + 1)^{2} = 4

What is 3x^2+3y^2-15x-21y=110 ?
The solution to 3x^2+3y^2-15x-21y=110 is Circle with (a,b)=(5/2 , 7/2),r=sqrt(331/6)