What is x^2+4x+y^2-14y=-3 ?

The solution to x^2+4x+y^2-14y=-3 is Circle with (a,b)=(-2,7),r=5sqrt(2)

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x^2+4x+y^2-14y=-3

x^{2} + 4 x + y^{2} - 14 y = - 3

(a, b) = (- 2, 7), r = 52

Solution steps

x^{2} + 4 x + y^{2} - 14 y = - 3

Rewrite

x^{2} + 4 x + y^{2} - 14 y = - 3

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 7)^{2} = (52)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 7), r = 52

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

x^{2} + y^{2} + 28 x - 32 y + 448 = 0

3 x^{2} + 3 y^{2} = 243

x^{2} + 6 x + y^{2} = 16 y - 68

x^{2} + y^{2} + 2 x + \frac{10}{3} y - 16 = 0

What is x^2+4x+y^2-14y=-3 ?
The solution to x^2+4x+y^2-14y=-3 is Circle with (a,b)=(-2,7),r=5sqrt(2)