What is (x-8)^2+(y+3)^2=91 ?

The solution to (x-8)^2+(y+3)^2=91 is Circle with (a,b)=(8,-3),r=sqrt(91)

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(x-8)^2+(y+3)^2=91

(x - 8)^{2} + (y + 3)^{2} = 91

(a, b) = (8, - 3), r = 91

Solution steps

(x - 8)^{2} + (y + 3)^{2} = 91

Rewrite

(x - 8)^{2} + (y + 3)^{2} = 91

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 3))^{2} = (91)^{2}

Therefore the circle properties are:

(a, b) = (8, - 3), r = 91

x^{2} + y^{2} - 12 x - 10 y - 15 = 0

\frac{3}{2} x^{2} + \frac{3}{2} y^{2} = \frac{75}{2}

16 x^{2} + 16 y^{2} + 8 x - 32 = - 1

4^{2} = (x + 4)^{2} + (y - 0)^{2}

4 x^{2} + 4 y^{2} = 128

What is (x-8)^2+(y+3)^2=91 ?
The solution to (x-8)^2+(y+3)^2=91 is Circle with (a,b)=(8,-3),r=sqrt(91)