What is x^2-12x+y^2-18y+92=0 ?

The solution to x^2-12x+y^2-18y+92=0 is Circle with (a,b)=(6,9),r=5

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x^2-12x+y^2-18y+92=0

x^{2} - 12 x + y^{2} - 18 y + 92 = 0

(a, b) = (6, 9), r = 5

Solution steps

x^{2} - 12 x + y^{2} - 18 y + 92 = 0

Rewrite

x^{2} - 12 x + y^{2} - 18 y + 92 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 9)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (6, 9), r = 5

x^{2} + y^{2} - 6 x - 4 y = 0

4 x^{2} + 4 y^{2} - 16 y + 15 = 0

2 x^{2} + 8 x + 2 y^{2} - 18 y = - \frac{33}{2}

x^{2} + 4 x + y^{2} - 14 y = - 3

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

What is x^2-12x+y^2-18y+92=0 ?
The solution to x^2-12x+y^2-18y+92=0 is Circle with (a,b)=(6,9),r=5