What is (x-1)^2+(y+2)^2+(x-4)^2+(y-6)^2=73 ?

The solution to (x-1)^2+(y+2)^2+(x-4)^2+(y-6)^2=73 is Circle with (a,b)=(5/2 ,2),r=(sqrt(73))/2

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(x-1)^2+(y+2)^2+(x-4)^2+(y-6)^2=73

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

(a, b) = (\frac{5}{2}, 2), r = \frac{73}{2}

Solution steps

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

Rewrite

(x - 1)^{2} + (y + 2)^{2} + (x - 4)^{2} + (y - 6)^{2} = 73

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - 2)^{2} = (\frac{73}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, 2), r = \frac{73}{2}

x^{2} + y^{2} + 28 x - 32 y + 448 = 0

3 x^{2} + 3 y^{2} = 243

x^{2} + 6 x + y^{2} = 16 y - 68

x^{2} + y^{2} + 2 x + \frac{10}{3} y - 16 = 0

17 = (x - 1)^{2} + (y + 1)^{2}

What is (x-1)^2+(y+2)^2+(x-4)^2+(y-6)^2=73 ?
The solution to (x-1)^2+(y+2)^2+(x-4)^2+(y-6)^2=73 is Circle with (a,b)=(5/2 ,2),r=(sqrt(73))/2