What is (x-1/2)^2+(y+1/4)^2= 64/25 ?

The solution to (x-1/2)^2+(y+1/4)^2= 64/25 is Circle with (a,b)=(1/2 ,-1/4),r= 8/5

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(x-1/2)^2+(y+1/4)^2= 64/25

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{8}{5}

Solution steps

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

Rewrite

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{8}{5})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{8}{5}

What is (x-1/2)^2+(y+1/4)^2= 64/25 ?
The solution to (x-1/2)^2+(y+1/4)^2= 64/25 is Circle with (a,b)=(1/2 ,-1/4),r= 8/5