What is (x-5)^2+(y-2)^2=1 ?

The solution to (x-5)^2+(y-2)^2=1 is Circle with (a,b)=(5,2),r=1

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(x-5)^2+(y-2)^2=1

(x - 5)^{2} + (y - 2)^{2} = 1

(a, b) = (5, 2), r = 1

Solution steps

(x - 5)^{2} + (y - 2)^{2} = 1

Rewrite

(x - 5)^{2} + (y - 2)^{2} = 1

in the form of the standard circle equation

(x - 5)^{2} + (y - 2)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (5, 2), r = 1

x, x^{2} + 400 x + p (x)^{2} + 250 p = 60000

x^{2} + y^{2} - 18 x - 9 = 0

- x^{2} - y^{2} + 4 x = 0

(x - 4)^{2} + y^{2} = 5^{2}

16 x^{2} + 16 y^{2} + 98 x - 40 y = 315

What is (x-5)^2+(y-2)^2=1 ?
The solution to (x-5)^2+(y-2)^2=1 is Circle with (a,b)=(5,2),r=1