What is 2x^2+2y^2+8x-12y-26=0 ?

The solution to 2x^2+2y^2+8x-12y-26=0 is Circle with (a,b)=(-2,3),r=sqrt(26)

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2x^2+2y^2+8x-12y-26=0

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

(a, b) = (- 2, 3), r = 26

Solution steps

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

Rewrite

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 26

What is 2x^2+2y^2+8x-12y-26=0 ?
The solution to 2x^2+2y^2+8x-12y-26=0 is Circle with (a,b)=(-2,3),r=sqrt(26)