What is x^2+16x+y^2+18y=-120 ?

The solution to x^2+16x+y^2+18y=-120 is Circle with (a,b)=(-8,-9),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

x^2+16x+y^2+18y=-120

x^{2} + 16 x + y^{2} + 18 y = - 120

(a, b) = (- 8, - 9), r = 5

Solution steps

x^{2} + 16 x + y^{2} + 18 y = - 120

Rewrite

x^{2} + 16 x + y^{2} + 18 y = - 120

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 9))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 9), r = 5

What is x^2+16x+y^2+18y=-120 ?
The solution to x^2+16x+y^2+18y=-120 is Circle with (a,b)=(-8,-9),r=5