What is 2x^2+2y^2+10x=12y+7 ?

The solution to 2x^2+2y^2+10x=12y+7 is Circle with (a,b)=(-5/2 ,3),r=(5sqrt(3))/2

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2x^2+2y^2+10x=12y+7

2 x^{2} + 2 y^{2} + 10 x = 12 y + 7

(a, b) = (- \frac{5}{2}, 3), r = \frac{5 3}{2}

Solution steps

2 x^{2} + 2 y^{2} + 10 x = 12 y + 7

Rewrite

2 x^{2} + 2 y^{2} + 10 x = 12 y + 7

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 3)^{2} = (\frac{5 3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 3), r = \frac{5 3}{2}

3 x^{(2)} = 9 - 3 y^{(2)} - 6 y

x^{2} + y^{2} + 10 x - 2 y = 55

4 x^{2} + 4 y^{2} - 16 y - 105 = 0

x^{2} + y^{2} + 4 x - 2 y = 1

x^{2} + y^{2} + 18 x + 17 = 0

What is 2x^2+2y^2+10x=12y+7 ?
The solution to 2x^2+2y^2+10x=12y+7 is Circle with (a,b)=(-5/2 ,3),r=(5sqrt(3))/2