What is 36x^2+36y^2-48x+36y-119=0 ?

The solution to 36x^2+36y^2-48x+36y-119=0 is Circle with (a,b)=(2/3 ,-1/2),r=2

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36x^2+36y^2-48x+36y-119=0

36 x^{2} + 36 y^{2} - 48 x + 36 y - 119 = 0

(a, b) = (\frac{2}{3}, - \frac{1}{2}), r = 2

Solution steps

36 x^{2} + 36 y^{2} - 48 x + 36 y - 119 = 0

Rewrite

36 x^{2} + 36 y^{2} - 48 x + 36 y - 119 = 0

in the form of the standard circle equation

(x - \frac{2}{3})^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{3}, - \frac{1}{2}), r = 2

x^{2} + y^{2} - 9 x + 4 y - 117 = 0

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

x^{2} + y^{2} + 12 x - 16 y = 0

a^{2} + b^{2} = 6

(x - 1)^{2} + (y - 5)^{2} = 81

What is 36x^2+36y^2-48x+36y-119=0 ?
The solution to 36x^2+36y^2-48x+36y-119=0 is Circle with (a,b)=(2/3 ,-1/2),r=2