What is 2x^2+2y^2=11 ?

The solution to 2x^2+2y^2=11 is Circle with (a,b)=(0,0),r=sqrt(11/2)

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2x^2+2y^2=11

2 x^{2} + 2 y^{2} = 11

(a, b) = (0, 0), r = \frac{11}{2}

Solution steps

2 x^{2} + 2 y^{2} = 11

Rewrite

2 x^{2} + 2 y^{2} = 11

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{11}{2}

x^{2} + y^{2} + 18 x + 2 y + 4 = 0

x^{2} + y^{2} + 4 x - 3 y - 1 = 0

2 (a^{2} + b^{2}) = (1003)^{2} + (103)^{2}

y^{2} = - x^{2} - 4 x + 12

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

What is 2x^2+2y^2=11 ?
The solution to 2x^2+2y^2=11 is Circle with (a,b)=(0,0),r=sqrt(11/2)