What is x^2+y^2+6x+14y+49=0 ?

The solution to x^2+y^2+6x+14y+49=0 is Circle with (a,b)=(-3,-7),r=3

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x^2+y^2+6x+14y+49=0

x^{2} + y^{2} + 6 x + 14 y + 49 = 0

(a, b) = (- 3, - 7), r = 3

Solution steps

x^{2} + y^{2} + 6 x + 14 y + 49 = 0

Rewrite

x^{2} + y^{2} + 6 x + 14 y + 49 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 7))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 7), r = 3

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

12 X^{2} + 12 Y^{2} = 144

2. 3^{2} = (x + 3)^{2} + (y - 1)^{2}

(x + 1)^{2} + (y + 3)^{2} = 4

What is x^2+y^2+6x+14y+49=0 ?
The solution to x^2+y^2+6x+14y+49=0 is Circle with (a,b)=(-3,-7),r=3