What is (x-20)^2+(y-24)^2=625 ?

The solution to (x-20)^2+(y-24)^2=625 is Circle with (a,b)=(20,24),r=25

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(x-20)^2+(y-24)^2=625

(x - 20)^{2} + (y - 24)^{2} = 625

(a, b) = (20, 24), r = 25

Solution steps

(x - 20)^{2} + (y - 24)^{2} = 625

Rewrite

(x - 20)^{2} + (y - 24)^{2} = 625

in the form of the standard circle equation

(x - 20)^{2} + (y - 24)^{2} = 2 5^{2}

Therefore the circle properties are:

(a, b) = (20, 24), r = 25

(x + 3)^{2} + (y - 5)^{2} = 85

(x - 5.5)^{2} + (y - 0.5)^{2} = 3.53

x^{2} + y^{2} - 20 x - 10 y = 5925

x^{2} - 1 x + y^{2} - 3 y - 20 = 0

(x - 2)^{2} + (y + 5)^{2} = \frac{1}{9}

What is (x-20)^2+(y-24)^2=625 ?
The solution to (x-20)^2+(y-24)^2=625 is Circle with (a,b)=(20,24),r=25