What is x^2+y^2+6x-12y+40=0 ?

The solution to x^2+y^2+6x-12y+40=0 is Circle with (a,b)=(-3,6),r=sqrt(5)

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x^2+y^2+6x-12y+40=0

x^{2} + y^{2} + 6 x - 12 y + 40 = 0

(a, b) = (- 3, 6), r = 5

Solution steps

x^{2} + y^{2} + 6 x - 12 y + 40 = 0

Rewrite

x^{2} + y^{2} + 6 x - 12 y + 40 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 6)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 6), r = 5

What is x^2+y^2+6x-12y+40=0 ?
The solution to x^2+y^2+6x-12y+40=0 is Circle with (a,b)=(-3,6),r=sqrt(5)