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Beliebt Geometry >

x^2+y^2<= 4x

Lösung

x^{2} + y^{2} \leq 4 x

Lösung

(a, b) = (2, 0), r = 2

Schritte zur Lösung

x^{2} + y^{2} \leq 4 x

Rewrite

x^{2} + y^{2} \leq 4 x

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 2

Graph

Beliebte Beispiele

3x^2+3y^2-24x-24y-51=0

3 x^{2} + 3 y^{2} - 24 x - 24 y - 51 = 0

(x-(-2))^2+(y-1)^2=4

(x - (- 2))^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} \leq 64

y^{2} + x^{2} = 64

y=x^{(2)}-4x+y^{(2)}

y = x^{(2)} - 4 x + y^{(2)}