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Beliebt Geometry >

x^2+y^2<= 64

Lösung

x^{2} + y^{2} \leq 64

Lösung

(a, b) = (0, 0), r = 8

Schritte zur Lösung

x^{2} + y^{2} \leq 64

Rewrite

x^{2} + y^{2} \leq 64

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 8

Graph

Beliebte Beispiele

y^{2} + x^{2} = 64

y=x^{(2)}-4x+y^{(2)}

y = x^{(2)} - 4 x + y^{(2)}

x^{2} - 6 x + y^{2} = 16

x^2-5/2 x+(y+2)^2=50

x^{2} - \frac{5}{2} x + (y + 2)^{2} = 50

(x-8)^2+(y-3)^2=sqrt(3)

(x - 8)^{2} + (y - 3)^{2} = 3